x=3,3x^-21/3x

Solution for x=3,3x^-21/3x equation:

x=3.3x^-21/3x

We move all terms to the left:

x-(3.3x^-21/3x)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We get rid of parentheses

x-3.3x^+21/3x=0

We multiply all the terms by the denominator


x*3x-(3.3x^)*3x+21=0

We multiply parentheses

-9x^2+x*3x+21=0

Wy multiply elements

-9x^2+3x^2+21=0

We add all the numbers together, and all the variables

-6x^2+21=0

a = -6; b = 0; c = +21;
Δ = b2-4ac
Δ = 02-4·(-6)·21
Δ = 504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{504}=\sqrt{36*14}=\sqrt{36}*\sqrt{14}=6\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{14}}{2*-6}=\frac{0-6\sqrt{14}}{-12}
=-\frac{6\sqrt{14}}{-12}
=-\frac{\sqrt{14}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{14}}{2*-6}=\frac{0+6\sqrt{14}}{-12}
=\frac{6\sqrt{14}}{-12}
=\frac{\sqrt{14}}{-2}
$